/13 Subnet

A /13 has 524,288 addresses, 524,286 of them usable by hosts. Its netmask is 255.248.0.0. Enter any address below to see its /13 network.

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Examples:

IPv4 network

524,286 usable hosts · 10.0.0.1 to 10.7.255.254

Private (RFC 1918)

Details

Netmask
Wildcard Mask
Broadcast
First Usable
Last Usable
Usable Hosts
Total Addresses
Netmask in Binary

Split Into Subnets

10.0.0.0/1410.0.0.0 – 10.3.255.255
10.4.0.0/1410.4.0.0 – 10.7.255.255

Subnet Calculator

/13 at a glance

CIDR Prefix/13
Netmask255.248.0.0
Wildcard Mask0.7.255.255
Netmask (Hex)0xFFF80000
Total Addresses524,288
Usable Hosts524,286
Host Bits19
Contains /24s2,048
Binary Mask11111111.11111000.00000000.00000000

A /13 fixes the first 13 bits of the address as the network and leaves 19 bits for hosts, so it holds 2^19 = 524,288 addresses. The first is the network address and the last is the broadcast address, leaving 524,286 for hosts.

A /13 is 2,048 /24 networks side by side; registries and ISPs allocate blocks this size to networks that route them on the internet.

A /13 can be announced in BGP on its own: /24 is the longest prefix most networks accept.

Other IPv4 Prefixes

/8/9/10/11/12/13/14/15/16/17/18/19/20/21/22/23/24/25/26/27/28/29/30/31/32

IPv6 Prefixes

IPv6 /32IPv6 /36IPv6 /40IPv6 /44IPv6 /48IPv6 /52IPv6 /56IPv6 /60IPv6 /64IPv6 /112IPv6 /126IPv6 /127IPv6 /128

Questions

How many usable IP addresses are in a /13?
524,286. A /13 has 524,288 addresses; the network and broadcast addresses are not usable by hosts.
What is the subnet mask for /13?
255.248.0.0. The wildcard (inverse) mask, used in Cisco ACLs, is 0.7.255.255.
How many /24 networks are in a /13?
2,048. Each step from /13 to /24 doubles the number of networks.
Is 255.248.0.0 the same as /13?
Yes. 255.248.0.0 written in binary is 13 ones followed by 19 zeros, which is what /13 means.

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